Y=22t^2+119.2t+479t

Solution for Y=22t^2+119.2t+479t equation:

=22Y^2+119.2Y+479Y

We move all terms to the left:

-(22Y^2+119.2Y+479Y)=0

We get rid of parentheses

-22Y^2-119.2Y-479Y=0

We add all the numbers together, and all the variables

-22Y^2-598.2Y=0

a = -22; b = -598.2; c = 0;
Δ = b2-4ac
Δ = -598.22-4·(-22)·0
Δ = 357843.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-598.2)-\sqrt{357843.24}}{2*-22}=\frac{598.2-\sqrt{357843.24}}{-44}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-598.2)+\sqrt{357843.24}}{2*-22}=\frac{598.2+\sqrt{357843.24}}{-44}
$